+364 with some logic we can figure out that
\(x=8\)
\(y=2\)
plug it in the equation,
\((8-2)\times(8^2-2^2)\)
\(6\times60\)
\(360\) of course, there's the other way around where x is 2 and y is 8
i'll leave that to you!
+876 "Other way around" is the same answer. Because here, you can consider absolute value since x and y are nonzero.
