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# help algebra

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if x+y=10, and xy=16, what is (x-y)*(x^2 - y^2)?

Jan 29, 2022

### 2+0 Answers

#1
+360
+3

with some logic we can figure out that

$$x=8$$

$$y=2$$

plug it in the equation,

$$(8-2)\times(8^2-2^2)$$

$$6\times60$$

$$360$$ of course, there's the other way around where x is 2 and y is 8

i'll leave that to you!

Jan 29, 2022
#2
+865
0

"Other way around" is the same answer. Because here, you can consider absolute value since x and y are nonzero.

MathProblemSolver101  Jan 29, 2022