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if x+y=10, and xy=16, what is (x-y)*(x^2 - y^2)?

 Jan 29, 2022
 #1
avatar+360 
+3

with some logic we can figure out that

\(x=8\)

\(y=2\)

plug it in the equation,

\((8-2)\times(8^2-2^2)\)

\(6\times60\)

\(360\) of course, there's the other way around where x is 2 and y is 8

i'll leave that to you!

 Jan 29, 2022
 #2
avatar+865 
0

"Other way around" is the same answer. Because here, you can consider absolute value since x and y are nonzero.

MathProblemSolver101  Jan 29, 2022

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