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One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48a^2 b$ and $a^2 b^5 = 6a^3 b$. What is the value of $b$ in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Nov 1, 2023
 #1
avatar+36919 
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a b^4 = 48 a^2 b 

b^3 = 48 a

b^3 / 48 = a 

 

Sub into second equation 

  b^6 / 2304 * b^5  =  6 b^9 /110592 * b 

b^11/ 2304 = 6b^10 / 110592 

b = 1/8     then      a = 1/24576

 Nov 1, 2023

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