+817 One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48a^2 b$ and $a^2 b^5 = 6a^3 b$. What is the value of $b$ in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
+37159 a b^4 = 48 a^2 b
b^3 = 48 a
b^3 / 48 = a
Sub into second equation
b^6 / 2304 * b^5 = 6 b^9 /110592 * b
b^11/ 2304 = 6b^10 / 110592
b = 1/8 then a = 1/24576
