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Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 34.

 Aug 21, 2021
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Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 34.     

 

Call the 1st integer (x)  

Call the 2nd integer (x + 2)  

Call the 3rd integer (x + 4)  

 

Given                                                  (x) + 2(x + 2) + 3(x + 4)  =  34  

Now, just multiply it out                         x + 2x + 4 + 3x + 12  =  34   

Combine like terms                              6x + 16  =  34  

Subtract 16 from both sides                6x  =  18  

Divide both sides by 6                          x  =  3  

 

The 1st integer is 3, the 2nd integer is 5, and the 3rd integer is 7  

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 Aug 22, 2021

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