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In class, we derived that
\frac{1}{n(n + 1)} = \frac{1}{n} - \frac{1}{n + 1}.

Fill in the blanks to make a true equation:

\frac{5x}{(x - 1)(x^2 + 2)(x + 7)^3)} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + 2} + \frac{D}{x + 7} + \frac{E}{(x + 7)^2} + \frac{F}{(x + 7)^3}

LiIIiam0216 Mar 21, 2024

hasAquestion · Answer 1 · 2024-03-21T10:53:06

In class, we derived that

$\frac{1}{n(n + 1)} = \frac{1}{n} - \frac{1}{n + 1}.$

Fill in the blanks to make a true equation:

$\frac{5x}{(x - 1)(x^2 + 2)(x + 7)^3)} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + 2} + \frac{D}{x + 7} + \frac{E}{(x + 7)^2} + \frac{F}{(x + 7)^3}$