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# HELP! Anyone know how to solve this?

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Jeri finds a pile of money with at least $200. If she puts$80 of the pile in her left pocket, gives away $$\frac{1}{3}$$ of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away \$200 of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)

Plz help.  I need an answer fast.

Sep 26, 2022

#1
+1015
+3

Say the amount of money in the original pile was "x". Then the inequality we can set up is x >= 200

80 is in the left pocket

(x - 80)/3 is the amount given away, and x - 80 - (x-80)/3 is the amount in the right pocket.

Total amount of money left over would be 80 + (x - 80 - (x-80)/3) > x - 200

x - (x-80)/3 > x - 200

(80-x)/3 > -200

80 - x > -600

200 =< x < 680

x = [200, 680)

Sep 26, 2022
#2
+1

Thank you so much!  I think I understand this problem now!

Guest Sep 27, 2022