Amaya and Bo each roll a fair, ordinary six-sided die with the numbers 1,2,3,4,5,6 on the sides. What is the probability that Amaya rolls a greater number than Bo? Enter your answer as a fraction in simplified form.

There are 36 possible outcomes

The number of rolls where Amaya's roll is greater than Bo's is

5 + 4 + 3 + 2 + 1 = 15

So....the probability is

15 / 36 =

5 / 12