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Amaya and Bo each roll a fair, ordinary six-sided die with the numbers 1,2,3,4,5,6 on the sides. What is the probability that Amaya rolls a greater number than Bo?

Enter your answer as a fraction in simplified form.

SmartMathMan  Jan 17, 2018
 #1
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There are 36 possible outcomes

 

The number of rolls where Amaya's roll is greater than Bo's  is

 

5  +  4  +  3  +  2   + 1  =  15

 

So....the probability is  

 

15 / 36   =

 

5  / 12

 

 

cool cool cool

CPhill  Jan 17, 2018

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