+12 The graph of a certain quadratic \(y = ax^2 + bx + c\) is a parabola with vertex (-4, 0) which passes through the point (1, -75). What is the value of a?
+118609 hint
The roots will be at \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
the axis of symentry will be the half way point between these roots.
What will that be, as fa as the formula is concerned ?
Sketch it if you are confused.
the vertex is on the axis of symmetry. so x=-4
Try taking it from here.
