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# Help appreciated!

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The graph of a certain quadratic $$y = ax^2 + bx + c$$ is a parabola with vertex (-4, 0) which passes through the point (1, -75). What is the value of a?

Jul 20, 2022

#1
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hint

The roots will be at       $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

the axis of symentry will be the half way point between these roots.

What will that be, as fa as the formula is concerned ?

Sketch it if you are confused.

the vertex is on the axis of symmetry.  so x=-4

Try taking it from here.

Jul 20, 2022