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The graph of a certain quadratic \(y = ax^2 + bx + c\) is a parabola with vertex (-4, 0) which passes through the point (1, -75). What is the value of a?

 Jul 20, 2022
 #1
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hint

 

The roots will be at       \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

 

the axis of symentry will be the half way point between these roots.  

What will that be, as fa as the formula is concerned ?  

Sketch it if you are confused.  

the vertex is on the axis of symmetry.  so x=-4

 

Try taking it from here.

 Jul 20, 2022

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