+610 Segment $s_1$ has endpoints at $(3+\sqrt{2},5)$ and $(4,7)$. Segment $s_2$ has endpoints at $(6-\sqrt{2},3)$ and $(3,5)$. Find the midpoint of the segment with endpoints at the midpoints of $s_1$ and $s_2$. Express your answer as $(a,b)$.
+128474 \( (3+\sqrt{2},5)$ and $(4,7)\)
\( (6-\sqrt{2},3)$ and $(3,5)\)
Midpoint of the 1st segment = ( [3 + √2 + 4']/2 , [7 + 5]/2 ) = ( [7 + √2] / 2 , 6)
Midpoint of the second segment = ( [ 6 - √2+ 3] / 2 , [5 + 3] / 2 ) = ( [ 9 - √2] / 2 , 4 )
The midpoint of these two segments is ( [ (7 + 9) / 2)/2 , [ 6 + 4 ]/ 2 ) =
(16/4, 10/2) =
( 4, 5 )
