If \(\displaystyle{f(x)=x^{(x+1)}(x+2)^{(x+3)}},\) then find the value of \(f(0)+f(-1)+f(-2)+f(-3)\).
Just sub in the numbers and then do the addition.
I will start you off
\(\displaystyle{f(x)=x^{(x+1)}(x+2)^{(x+3)}}\\ \displaystyle{f(0)=0^{(0+1)}(0+2)^{(0+3)}}\\ \displaystyle{f(0)=0^{1}*2^3}\\ \displaystyle{f(0)=0}\)
Notice that Guest used the word asap in his title. This is one of the things that most answerers don't like.
+321 
