If f(x)=x(x+1)(x+2)(x+3), then find the value of f(0)+f(−1)+f(−2)+f(−3).
Just sub in the numbers and then do the addition.
I will start you off
f(x)=x(x+1)(x+2)(x+3)f(0)=0(0+1)(0+2)(0+3)f(0)=01∗23f(0)=0
Notice that Guest used the word asap in his title. This is one of the things that most answerers don't like.