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# HELP ASAP PLZ

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In cyclic quadrilatera $$PQRS,$$

$$\frac{\angle P}{2} = \frac{\angle Q}{3} = \frac{\angle R}{4}.$$
Find the largest angle of quadrilateral PQRS, in degrees.

Apr 9, 2020

#1
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The sum of the opposite angles in a cyclic quadrilateral sum to 180 degrees.

Thus, p=2/3q, q=q, r=4/3q

2/3q+4/3q=180

6/3q=180

q=90

p=60

r=120

s=90

And, the largest angle is angle r, which measures 120 degrees.

Apr 9, 2020