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In cyclic quadrilatera \(PQRS,\)

\(\frac{\angle P}{2} = \frac{\angle Q}{3} = \frac{\angle R}{4}.\)
Find the largest angle of quadrilateral PQRS, in degrees.

 Apr 9, 2020
 #1
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The sum of the opposite angles in a cyclic quadrilateral sum to 180 degrees.

 

Thus, p=2/3q, q=q, r=4/3q

 

2/3q+4/3q=180

 

6/3q=180

 

q=90

 

p=60

 

r=120

 

s=90

 

And, the largest angle is angle r, which measures 120 degrees.

 Apr 9, 2020

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