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Trapezoid EFGH is inscribed in a circle, with \(EF \parallel GH\). If arc GH is 70 degrees, arc EH is \(x^2 - 2x\) degrees, and arc FG is \(56 - 3x\) degrees, where x > 0, find arc EPF, in degrees.

 Apr 9, 2020
 #1
avatar+20981 
+1

Hint:  arc(EH)  =  arc(GF)

 Apr 9, 2020
 #2
avatar+17 
+1

I already know that, but then what?

ilikepokemon2009  Apr 9, 2020
 #3
avatar+17 
+1

I got  \(x^2=56-x\), but then how do I proceed?

 Apr 9, 2020
 #4
avatar+17 
+1

Nvm I got it cool

ilikepokemon2009  Apr 9, 2020

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