Trapezoid EFGH is inscribed in a circle, with \(EF \parallel GH\). If arc GH is 70 degrees, arc EH is \(x^2 - 2x\) degrees, and arc FG is \(56 - 3x\) degrees, where x > 0, find arc EPF, in degrees.

Hint: arc(EH) = arc(GF)

I already know that, but then what?

I got \(x^2=56-x\), but then how do I proceed?

Nvm I got it