Trapezoid EFGH is inscribed in a circle, with EF∥GH. If arc GH is 70 degrees, arc EH is x2−2x degrees, and arc FG is 56−3x degrees, where x > 0, find arc EPF, in degrees.
Hint: arc(EH) = arc(GF)
I already know that, but then what?
I got x2=56−x, but then how do I proceed?
Nvm I got it
+20 
