A is a constant such that the graph of the equation Ax-3y=6 passes through the point (1,-3). Find A.
We plug in the given point into the equation Ax-3y=6.
We then have:
A(1)-3(-3)=6
A+9=6
A=-3
Ax - 3y = 6 and x = -1 and y = -3:
A(-1) - 3(-3) = 6
-A + 9 = 6
-A = -3
A = 3
geno, I believe you plugged in the wrong x value.
I did -- thank you!
No problem.
+334 
+781 
