#1**0 **

*Find angle BPC*

angle PBC = 150^{o} which is the total of PBA (60^{o} cuz the triangle is equilateral) plus ABC (90^{o} cuz it says so)

since PBC is 150^{o} that leaves __30 ^{o} for the total of both BPC and BCP__ cuz the total of angles in a triangle is 180

triangle PBC is isoceles since sides PB and BC are equal

therefore angles BPC and BCP are equal, so each one is half of their 30^{o} total

so angle **BPC is 15 ^{o}** cuz 15 is half of 30

_{.}

Guest Sep 16, 2021