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The real numbers $x$, $y$, $z$, satisfy $0\leq x \leq y \leq z \leq 4$. If their squares form an arithmetic progression with common difference $2$, determine the minimum possible value of $|x-y|+|y-z|$.

 Oct 14, 2019
 #1
avatar+105700 
+3

I do not consider looking at questions with lots of totally irrelevant and hard to read LaTex. 

 

If you are too lazy to remove the confusing dollar signs then quite likely you have not even attempted the question yourself anyway.

 Oct 15, 2019
 #2
avatar+104962 
+2

$T$H$A$N$K$S$, $M$E$L$O$D$Y$

 

[LOL!!!!]

 

 

cool cool cool

CPhill  Oct 15, 2019
 #3
avatar+2417 
+1

If you are too lazy to remove the confusing dollar signs then quite likely you have not even attempted the question yourself anyway.​

 

So True!

CalculatorUser  Oct 17, 2019

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