If we express $3x^2 - 6x - 2$ in the form $a(x - h)^2 + k$, then what is $a + h + k$?
Let's use some clever algebraic manipulation to change this quadratic from standard from to vertex form.
f(x)=3x2−6x−2f(x)=3(x2−2x)−2f(x)=3(x2−2x+1)−2−3f(x)=3(x−1)2−5a=3 and h=1 and k=−5a+h+k=3+1−5a+h+k=−1