In triangle ABC the angle bisectors are AD BE and CF, which intersect at the incenter I. If Angle ACB = 38 degrees then find the measure of AIE in degrees.
I am stuck on this problem and I don't know what to do.
+1694 In triangle ABC the angle bisectors are AD BE and CF, which intersect at the incenter I. If Angle ACB = 38 degrees then find the measure of AIE in degrees.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Let angle BAC be 90 degrees
∠IAE = 45º
∠AEI = 90 - 1/2(∠ABC) = 64º
∠AIE = 180 - (∠IAE + ∠AEI) = 71º
Shortcut:::
∠AIE = 90 - 1/2(∠ACB) 
