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In triangle ABC the angle bisectors are AD BE  and CF, which intersect at the incenter I. If Angle ACB = 38 degrees then find the measure of AIE in degrees.

 

I am stuck on this problem and I don't know what to do.

 Jul 28, 2021
 #1
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What is an angle bisector?

 Jul 28, 2021
 #2
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Angle AIB = 111 degrees.

 Jul 28, 2021
 #3
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Why do you say this?

Guest Jul 28, 2021
 #4
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In triangle ABC the angle bisectors are AD BE  and CF, which intersect at the incenter I. If Angle ACB = 38 degrees then find the measure of AIE in degrees.

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Let angle BAC be 90 degrees

 

∠IAE = 45º

 

∠AEI = 90 - 1/2(∠ABC) = 64º

 

∠AIE = 180 - (∠IAE + ∠AEI) = 71º

 

Shortcut:::

 

∠AIE = 90 - 1/2(∠ACB) smiley

 Jul 28, 2021
 #5
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Where did you get 90 for BAC?

Guest Aug 4, 2021

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