+22 | X | P(x) |
| 0 | 0 |
| 1 | 3/10 |
| 2 | 6/10 |
| 3 | 1/10 |
Total=10/10=1
A three-member committee is selected randomly from a group consisting of three men and two women. Let x denote the number of men on the committee. and complete the probability distribution table. (Hint: Calculate the number of combinations of picking three men from the five members total in the committee for the total of each of your probabilities)
Find the probability that the committee members are all men
Find the expected number of men on the committee
the probabilty of picking a man the first pick is 3/5
the probabilty of picking a man the second pick is 2/4
the probabilty of picking a man the third pick is 1/3
multiply those together and you get 6/60 chance or 1/10th they are all men
in that case the probability of picking 2 men is 6/20 or 3/10th
you table just has the 3/10 and 6/10 backwards cause 3/5 = 6/10
