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# Help ASAP!!!

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Suppose \(3b-4a = 24\). Given that \(a \) and \(b\) are consecutive integers, and b

Aug 8, 2022
edited by Guest  Aug 8, 2022
edited by Guest  Aug 8, 2022
edited by Guest  Aug 8, 2022

#7
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There are 2 cases to consider: \(a = b + 1 \) and \(b = a + 1\)

So, we have 2 systems:

\(3a - 4b = 24\)

\(a = b + 1\)

AND

\(3a - 4b = 24\)

\(b = a + 1\)

The solutions for the two systems, respectively in the form of \((a,b)\), are \(\color{brown}\boxed{-20, -21}\) and \(\color{brown}\boxed{-28, -27}\)

Aug 8, 2022

#1
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LOL, the formatting is off. The unfinished part is "and b

Aug 8, 2022
#2
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Thanks so much in advance!!!

Guest Aug 8, 2022
#3
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Are you sure your question is formatted properly?

It just ends with ",and b"...

Aug 8, 2022
#4
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I'm trying to make it work but it is glitching.

"and b

Guest Aug 8, 2022
#5
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Maybe try typing your question without LaTex

Aug 8, 2022
edited by BuilderBoi  Aug 8, 2022
#6
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Suppose 3b-4a = 24. Given that a and b are consecutive integers, and b

Guest Aug 8, 2022
#7
+2667
0

There are 2 cases to consider: \(a = b + 1 \) and \(b = a + 1\)

So, we have 2 systems:

\(3a - 4b = 24\)

\(a = b + 1\)

AND

\(3a - 4b = 24\)

\(b = a + 1\)

The solutions for the two systems, respectively in the form of \((a,b)\), are \(\color{brown}\boxed{-20, -21}\) and \(\color{brown}\boxed{-28, -27}\)

BuilderBoi Aug 8, 2022