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Suppose \(3b-4a = 24\). Given that \(a \) and \(b\) are consecutive integers, and b

 Aug 8, 2022
edited by Guest  Aug 8, 2022
edited by Guest  Aug 8, 2022
edited by Guest  Aug 8, 2022

Best Answer 

 #7
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There are 2 cases to consider: \(a = b + 1 \) and \(b = a + 1\)

 

So, we have 2 systems:

 

\(3a - 4b = 24\)

\(a = b + 1\)

 

AND
 

\(3a - 4b = 24\)

\(b = a + 1\)

 

The solutions for the two systems, respectively in the form of \((a,b)\), are \(\color{brown}\boxed{-20, -21}\) and \(\color{brown}\boxed{-28, -27}\)

 Aug 8, 2022
 #1
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LOL, the formatting is off. The unfinished part is "and b

 Aug 8, 2022
 #2
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Thanks so much in advance!!!

Guest Aug 8, 2022
 #3
avatar+2444 
0

Are you sure your question is formatted properly?

 

It just ends with ",and b"...

 Aug 8, 2022
 #4
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I'm trying to make it work but it is glitching.

 

"and b

Guest Aug 8, 2022
 #5
avatar+2444 
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Maybe try typing your question without LaTex

 Aug 8, 2022
edited by BuilderBoi  Aug 8, 2022
 #6
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0

Suppose 3b-4a = 24. Given that a and b are consecutive integers, and b

Guest Aug 8, 2022
 #7
avatar+2444 
0
Best Answer

There are 2 cases to consider: \(a = b + 1 \) and \(b = a + 1\)

 

So, we have 2 systems:

 

\(3a - 4b = 24\)

\(a = b + 1\)

 

AND
 

\(3a - 4b = 24\)

\(b = a + 1\)

 

The solutions for the two systems, respectively in the form of \((a,b)\), are \(\color{brown}\boxed{-20, -21}\) and \(\color{brown}\boxed{-28, -27}\)

BuilderBoi Aug 8, 2022

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