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# help asap

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Two regular polygons have the same perimeter. If the first has 38 sides and a side length twice as long as the second, how many sides does the second have?

Mar 20, 2021

#1
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The first polygon will have side length will be set to 2x. So, the perimeter of the polygon is 76x. (because 38 * 2x = 76x)

The second polygon will have side length will be set to x, because the second polygon has half the side length of the first polygon. Also, the number of sides that the polygon has will be set to y. So, the perimeter will be xy.

The perimeters of both polygons are equal, so we can set 76x = xy.

Divide both sides by x to get:

76 = y

There are 76 sides in the second polygon.

Mar 20, 2021

#1
+17
+1

The first polygon will have side length will be set to 2x. So, the perimeter of the polygon is 76x. (because 38 * 2x = 76x)

The second polygon will have side length will be set to x, because the second polygon has half the side length of the first polygon. Also, the number of sides that the polygon has will be set to y. So, the perimeter will be xy.

The perimeters of both polygons are equal, so we can set 76x = xy.

Divide both sides by x to get:

76 = y

There are 76 sides in the second polygon.

skylersnoop Mar 20, 2021