+6248 You can see two points on this line (0,1) and (2,0). From this we can find the line.
\(\text{the slope }m \text{ is given by}\\ m=\dfrac{y_2-y_1}{x_2-x_1} = \dfrac{0-1}{2-0} = -\dfrac 1 2\\ \text{using the first point and the slope we write the point slope form of the line}\\ (y-1) = -\dfrac 1 2 (x-0)\\ \text{and with a bit of algebra we get }\\ \dfrac 1 2 x +y= 1 \text{ or}\\ x+2y = 2\)
+6248 You can see two points on this line (0,1) and (2,0). From this we can find the line.
\(\text{the slope }m \text{ is given by}\\ m=\dfrac{y_2-y_1}{x_2-x_1} = \dfrac{0-1}{2-0} = -\dfrac 1 2\\ \text{using the first point and the slope we write the point slope form of the line}\\ (y-1) = -\dfrac 1 2 (x-0)\\ \text{and with a bit of algebra we get }\\ \dfrac 1 2 x +y= 1 \text{ or}\\ x+2y = 2\)
