+0  
 
+1
111
4
avatar+57 

Bill and Betty do chores at home. Bill mows the lawn every 8 days, and

Betty bathes the dog every 14 days. Suppose Bill and Betty do their

chores today. How many days will pass before they both do their

chores on the same day again?

 Nov 26, 2020
 #1
avatar+40 
+3

To do this question you need to find the least common factor of 8 and 14, which is 80 so 80 days pass before they do their chores on the same day

 Nov 26, 2020
 #2
avatar+57 
+1

thank u very much!

mav002  Nov 26, 2020
 #4
avatar
0

 

"least common factor of 8 and 14, which is 80"    No, it is not.

Guest Nov 28, 2020
edited by Guest  Nov 28, 2020
 #3
avatar
0

 

Bill and Betty do chores at home. Bill mows the lawn every 8 days, and

Betty bathes the dog every 14 days. Suppose Bill and Betty do their

chores today. How many days will pass before they both do their

chores on the same day again?  

 

After 112 days, Bill will have mown the lawn 14 times  

               and Betty will have bathed the dog 8 times. 

 

I got 112 by just multiplying 8 x 14.  

 

We know 112 works, but can we halve it though?  

Let's see what happens after 56 days. 

 

After 56 days, Bill will have mown the lawn 7 times  

           and Betty will have bathed the dog 4 times. 

 

Can we halve it again?  14 would go into 28 but 8 won't. 

 

So it looks like they do these chores on the same day every 56 days   

.

 Nov 27, 2020

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