How many of the natural numbers from $1$ to $800,$ inclusive, contain the digit $6$ at least twice? (The numbers $266$ and $663$ are two natural numbers that contain the digit $6$ at least twice, but $430$ or $16$ are not.)
66 166 266 366 466 566 606 616 626 636 646 656 660 661 662 663 664 665 666 667 668 669 676 686 696 766 >> Total = 26
That is correct!
