+0  
 
0
30
3
avatar

The equation $y = -6t^2 + 51t$ describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 108 feet in height?

 Nov 2, 2020
 #1
avatar
0

108 = -6t^2+ 51t

-6t^2+51t-108 = 0     Use Quadratic Formula    a = -6   b = 51   c = -108    

                                      you will get two values of t ....one is on the way up..... the other is on the way down....

 Nov 2, 2020
 #2
avatar
0

So which solution would it be, 2, or 9/4

Guest Nov 2, 2020
 #3
avatar
0

Better check you calculations again....and OF COURSE it will be the shorter time !!!!!!!!!!!!!!!!!!!!!!!!

Guest Nov 2, 2020

31 Online Users

avatar
avatar
avatar