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If \(\log_{25}(x-4)=\frac{1}{2}\) find \(\frac{1}{\log_{x}3}\)

 Jul 25, 2020
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you have to solve for x first.

 

\(log_{25}(x-4)=0.5\\ \text{can be rearranged as }\\ x-4=25^{0.5}\)

 

you can take it from there.

 

Just remember that the LOG of something is a POWER.

I just remember this and then I do my other rearrangements the same way

 

 \(10^2=100\)    

 

  \(log_{10}100=2\)

 Jul 29, 2020

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