Solve for \(x>0\) in the following arithmetic sequence: \(1^2, x^2, 3^2\).
we know that 1^2=1 and 3^2=9 so x=sqrt((1+9)/2)=sqrt(10/2)=sqrt5 so out=r final answer is \(\boxed{x=\sqrt5}\)
At first glance, it would appear that x = 2 but that would not be an arithmetic sequence.
With the values multiplied out, we get 1, x2, 9 and so x2 has to be 5. therefore x = sqrt(5)
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