1) Evaluate \(|2\omega^2-4\omega-30|\) if \(\omega=1-5i.\)
2) Solve 2z + i = iz + 3. Express your answer in the form x + yi.
\(|2\omega^2-4\omega - 30| = \\ |2(1-5i)^2 -4(1-5i)-30| = \\ |2(1-10i-25)-4+20i-30|=\\ |-48 -20i - 34 + 20i|= 82\)
\(2z+i = iz + 3\\ (2-i)z = 3-i\\ z = \dfrac{3-i}{2-i} = \dfrac{(3-i)(2+i)}{5}=\dfrac 7 5 + i \dfrac 1 5\)
