What is the area in square units of the convex quadrilateral with vertices (-1, 0), (0, 1), (-2, 0) and (0, -3)?
PLot the points on the coordinate plane...then repost what you graphed for help.....
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We have two obtuse triangles ABC and ACD
Both have bases of 1 and heights of 1 and 3 respectively
Total area = (1/2) (1) ( 1 + 3) = 2 units^2
+37146 
