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What is the area in square units of the convex quadrilateral with vertices (-1, 0), (0, 1), (-2, 0) and (0, -3)?

 Jun 14, 2021
 #1
avatar+35066 
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PLot the points on the coordinate plane...then repost what you graphed for help.....

 Jun 14, 2021
 #2
avatar+121063 
+1

See here

 

 

We  have two  obtuse triangles ABC  and  ACD

 

Both  have  bases  of  1     and heights  of  1  and 3  respectively

 

Total  area  =  (1/2) (1)  ( 1 + 3)  =    2  units^2

 

 

cool cool cool

 Jun 14, 2021

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