Find the coordinates of the center of the circle.
The points on the circle are (22,15), (-25,0), (22,-29).
Using the square of the distances to equate R^2
(x - 22)^2 + (y - 15)^2 = (x -22)^2 + ( y + 29)^2
y^2 - 30y + 225 = y^2 + 58y + 841
-30y - 58y = 841 - 225
-88y = 616
y = -616 / 88 = -7
To find x
(x -22)^2 + (-7-15)^2 = (x + 25)^2 + ( -7 -0)^2
x^2 - 44x + 484 + 484 = x^2 + 50x + 625 + 49
-44x + 968 = 50x + 674
968 - 674 = 50x + 44x
294 = 94x
x = 294/94 = 147 / 47
Center = ( 147/47 , -7)