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How many different positive integers divisible by 4 can be formed using at least one of the digits 1, 2, 3, 4, and 6 exactly once and no other digits? For example, 12 counts, but 512 does not.

 Feb 25, 2022
 #1
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You can form 36 numbers as follows:

 

(1236, 1264, 1324, 1364, 1432, 1436, 1624, 1632, 2136, 2164, 2316, 2364, 2416, 2436, 3124, 3164, 3216, 3264, 3412, 3416, 3612, 3624, 4132, 4136, 4216, 4236, 4312, 4316, 4612, 4632, 6124, 6132, 6312, 6324, 6412, 6432) >>Total = 36 such numbers.

 Feb 25, 2022
 #2
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I don't understand what is being asked for.    frown

 Feb 26, 2022

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