How many 4-digit numbers have the second digit even and the fourth digit is at most twice the second digit? (Here, digits are read from the left, so the first digit is the leftmost digit, and so on.)
+2666 There are 2 cases: The second digit is a 2 or it is a 4
If the second digit is a 2: \(9 \times 1 \times 10 \times 5 = 450\)
If the second digit is a 4: \(9 \times 1 \times 10 \times 9 = 810\)
Add these together for a total of \(\color{brown}\boxed{1,260}\) ways
+36916 the fourth digit is at most twice the second digit .... I think you may need to recalculate .....
second digit = 0 fourth = 0
2 fourth 0 1 2 3 4
4 fourth 0 - 8
6 fourth 0-9
8 fourth 0-9 Right?
+118608 How many 4-digit numbers have the second digit even and the fourth digit is at most twice the second digit? (Here, digits are read from the left, so the first digit is the leftmost digit, and so on.)
0 0 9*10 = 90
2, (0,1,2) 9*10*3 = 270
4, (0-8) 9*10*9 = 810
6 (0-9) 9*10*10=900
8 (0-9) 9*10*10=900
90+270+810+1800 = 2970
