+0

# Help CPhill

0
39
1

Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7,2) and is parallel to the graph of x + 3y = -5.

Here is what I have got so far: In the problem it says that  is parallel to our graph, Ax+By=3. Obviously, graphs that are parallel must have the same slope. Now, we should turn  into slope form. Divide everything by 3. Y=-x/3-5/3. Therefore, we have a slope of -1/3. So now we have -1/3x+By=3. Now we have got a as -1/3. Now we have to find B. We can substitute the point -7,2 into the equation. This will get us 7/3+2B=3. This will get B as 1/3. Now we need to do B-A 1/3-(-1/3). This will get us 2/3 and that is marked as wrong.

Jun 2, 2022

#1
+1750
+1

The error in your work is that you substitute $$-{1 \over 3}$$ for $$A$$.

To avoid this error, you should first solve for the line of the equation in slope-intercept form, then convert it into standard form.

Let the line of the equation be $$y = mx + b$$. We already know that the slope is $$-{1 \over 3}$$, so we can substitute that in for m.

This gives us: $$y = -{1 \over 3}x + b$$. Now, plug in the point $$(-7,2)$$. This gives us: $$2 = -{1 \over 3} \times 7 + b$$, and we can solve for b, giving us $$b = - {1 \over3}$$.

Now we have the equation: $$y = -{1 \over 3} x - {1 \over 3}$$

Can you take it from here?

Jun 2, 2022