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Find all real constants  such that the system

 

x+3y=kx,3x+y=ky.
has a solution other than $(x,y)=(0,0).$

 Jun 18, 2020
 #1
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I'm assuming that you mean "all real constants k"

First add the two equations together. 

4(x+y)=k(x+y). k = 4

Then subtract the two. 

2(xy)=k(xy). k = -2.

So our two solutions are k = 4, -2

 Jun 18, 2020

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