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Suppose \(f\) is a polynomial such that\(f(0)=47, f(1)=32, f(2)=-13\) and \(f(3)=16 \). What is the sum of the coefficients of \(f \)?

 Mar 24, 2019

Best Answer 

 #2
avatar+533 
+2

We know that the sum of the coefficients is found by plugging in 1 into the polynomial. We are given f(1) as 32, so the answer is 32.

 Mar 24, 2019
 #1
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*****

 

 

cool cool cool

 Mar 24, 2019
edited by CPhill  Mar 24, 2019
 #3
avatar+533 
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The constant is a coefficient of x^0. I think you are incorrect. :)

asdf335  Mar 24, 2019
 #2
avatar+533 
+2
Best Answer

We know that the sum of the coefficients is found by plugging in 1 into the polynomial. We are given f(1) as 32, so the answer is 32.

asdf335 Mar 24, 2019

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