Suppose \(f\) is a polynomial such that\(f(0)=47, f(1)=32, f(2)=-13\) and \(f(3)=16 \). What is the sum of the coefficients of \(f \)?
We know that the sum of the coefficients is found by plugging in 1 into the polynomial. We are given f(1) as 32, so the answer is 32.
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The constant is a coefficient of x^0. I think you are incorrect. :)
