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  1. 516-(x2-x) = 25 - (x2-8)​ The "2" numbers are exponents (bn)
  2. 254x = 1/5x2

 

Please, I really need help.

 Oct 18, 2017
edited by chaconsara32  Oct 18, 2017
 #1
avatar+98125 
+2

Hard to read the frst one but I assume this is :

 

1. 516 -(x^2 - x)  =  25-(x^2 - 8)   simplify as

 

   5 -x^2 + x + 16  =  (52) 8 - x^2 

 

    5 -x^2 + x + 16  =  516 -x^2      

 

Since the bases are the same.....solve for the exponents

 

-x^2 + x + 16   =   16  - x^2    subtract x^2 from both sides

 

x + 16  =  16       subtract 16 from both sides

 

x  = 0

 

 

cool cool cool

 Oct 18, 2017
 #2
avatar+50 
+1

Yes, it is like that laugh I still need to get the hang of writing these on a computer! Thanks!

chaconsara32  Oct 18, 2017
edited by chaconsara32  Oct 18, 2017
 #3
avatar+98125 
+2

Here's the second one

 

254x  = (1/5)x^2

 

Note that 1/5  =  5^-1    and 25  = 5^2 ....so we have....

 

(5^2)4x =  (5^-1)x^2

 

58x =  5-x^2    the bases are the same....solve for the exponents

 

8x  = -x^2     add x^2 to both sides

 

x^2 + 8x  = 0      factor

 

x ( x + 8)  = 0       set both factors to 0  and solve for x and we get that

 

x = 0    or   x  = -8

 

 

cool cool cool

 Oct 18, 2017
 #4
avatar+50 
+1

Thank you very much for your help! (☞゚ヮ゚)☞ ☜(゚ヮ゚☜)

chaconsara32  Oct 18, 2017

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