help fast please

In general: $(\frac{m}{n})=\frac{m!}{n!(m-n)!}$

so:    

  $(\frac{4}{0})=1\\ (\frac{5}{1})=5\\ (\frac{6}{2})=15 \\ (\frac{7}{3})=35$

I’ll leave you to add up the numbers!

(Note that 0! = 1)

Note that 

C(n, 0) + C(n+1,1) + C(n + 2, 2) + C(n + 3, 3) +.....+ C(n + m, m)  = C(n + m + 1, m)

So

C(4,0)  + C(5, 1) + C(6,2) + C(7,3)  = C(8,3)   = 56