Let x,y,z be nonzero real numbers, such that no two are equal, and
x+1y=y+1z=z+1x.
Find all possible numeric values of xyz
I got 1 as one of the answers.
Ok, first off, let's split the one equation into a system of equations so that each term is equal to another. We get
x+1/y=y+1/zx+1/y=z+1/xy+1/z=z+1/x
I won't really show the steps, although I will if needed. Let me know if you want to.
(x,y,z)=(−1z−1,z−1z,z)(x,y,z)=(−1z+1,−z+1z,z)
We want to find the value of xyz since we need the product.
Thus, multiplying these together, we get
(−1z−1)(z−1z)z=−1z−1(z−1)=−1
(−1z+1)(−z+1z)z=1zz=1
So good job! You were correct about 1. The other value is -1.
I didn't go into too much detail, but let me know if you need more assistance.
Thanks! :)