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Let x,y,z  be nonzero real numbers, such that no two are equal, and

x+1y=y+1z=z+1x.

Find all possible numeric values of xyz

I got 1 as one of the answers. 

 Jul 23, 2024
 #1
avatar+1950 
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Ok, first off, let's split the one equation into a system of equations so that each term is equal to another. We get

x+1/y=y+1/zx+1/y=z+1/xy+1/z=z+1/x

 

I won't really show the steps, although I will if needed. Let me know if you want to. 

(x,y,z)=(1z1,z1z,z)(x,y,z)=(1z+1,z+1z,z)

 

We want to find the value of xyz since we need the product. 

Thus, multiplying these together, we get

(1z1)(z1z)z=1z1(z1)=1

(1z+1)(z+1z)z=1zz=1

 

So good job! You were correct about 1. The other value is -1. 

I didn't go into too much detail, but let me know if you need more assistance. 

 

Thanks! :)

 Jul 23, 2024
edited by NotThatSmart  Jul 23, 2024
 #2
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Thanks again. I think I can fill in the gaps!

MeldHunter  Jul 23, 2024
 #3
avatar+1950 
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Glad I can help!

Hope you understood my explenation!

Nice work! :)

 

~NTS

NotThatSmart  Jul 23, 2024
edited by NotThatSmart  Jul 24, 2024

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