The shape ABCD is made from a rectangle ANCD and the right-angled triangle NBC.
ANB is a straight line.
AN = 9 cm.
NB = 5 cm.
The area of rectangle ANCD is 36 cm2
Work out the area of shape ABCD.
Thanks for the A2A.
36/9 = 4.
4*5 = 20/2 = 10
10+36 = 46 \({cm}^{2}\)
Cheers!
Thanks for the A2A.
36/9 = 4.
4*5 = 20/2 = 10
10+36 = 46 \({cm}^{2}\)
Cheers!