We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
132
2
avatar

Find the area between f(x) = x^3 + 2 and the x-axis from -1 to 2

 

Find the area between f(x) = sinx and the x axis from 0 to 3π/4

 

Thank youuu!

 Mar 24, 2019
 #1
avatar+30 
+1

1. \(\text{We can use an integral: } \int^{2}_{-1}( x^3 + 2) dx = ? \text{ We now find the antiderivative of } x^3+2\\ \text{which turns out to be } \frac{1}{4} x^4 \text{. Then, we plug it in:} \frac{1}{4}(2)^4 - \frac{1}{4}(-1^4) = \frac{17}{4}. \)

 

2. \(\text{We use another integral: } \int^{3\pi/4}_{0} \sin x \: dx. \text{Take the antiderivative of }\sin x \text{, which is just }-\cos x. \text{Thus, the answer is }\\ -\cos(\frac{3\pi}{4}) - ( -\cos 0) = \frac{\sqrt{2}}{2} + 1. \)

.
 Mar 24, 2019
 #2
avatar+102792 
0

Please do not gimake a habit of giving answers like this.

You have just done guests homework for them but there is no reason to think that you have taught anyone anything.

 

A much better answer would be to explain what area and integrals have to do with each other etc etc.

Teaching answers take a lot longer to construct but they maybe  of learning value.

 Mar 24, 2019

11 Online Users

avatar