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Two fair, six-sided dice are rolled. They are marked so one die has the numbers 1, 3, 5, 7, 9, 11 and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled is divisible by 5? Express your answer as a common fraction.

 Apr 13, 2022
 #1
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+1

36 possible rolls

multiples of 5

14

32

312

510

78

96

             6 out of 36   = 1/6

 Apr 13, 2022
 #2
avatar+1382 
+1

There are 6 x 6 = 36 options

 

Of these, 14 of them work: 

 

1 + 4

4 + 1

3 + 2 

2 + 3 

6 + 9

9 + 6

7 + 8

8 + 7

11 + 4

4 + 11

3 + 12

12 + 3

10 + 5

5 + 10

 

Thus, the probability is \({14 \over 36} = \color{brown}\boxed{7 \over 18}\)

 Apr 13, 2022
 #3
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+1

thank you

Guest Apr 13, 2022
 #4
avatar+36417 
0

1 + 4

4 + 1

3 + 2 

2 + 3 

6 + 9

9 + 6

7 + 8

8 + 7

11 + 4

4 + 11

3 + 12

12 + 3

10 + 5

5 + 10

                     Can't roll the red ones AND the black ones above each red..... the dice are marked differently......

                          first answerer missed    11 - 4      so correct answer is    7 out of 36      or   7/36 

ElectricPavlov  Apr 14, 2022

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