Two fair, six-sided dice are rolled. They are marked so one die has the numbers 1, 3, 5, 7, 9, 11 and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled is divisible by 5? Express your answer as a common fraction.
+2668 There are 6 x 6 = 36 options
Of these, 14 of them work:
1 + 4
4 + 1
3 + 2
2 + 3
6 + 9
9 + 6
7 + 8
8 + 7
11 + 4
4 + 11
3 + 12
12 + 3
10 + 5
5 + 10
Thus, the probability is \({14 \over 36} = \color{brown}\boxed{7 \over 18}\)
+37157 1 + 4
4 + 1
3 + 2
2 + 3
6 + 9
9 + 6
7 + 8
8 + 7
11 + 4
4 + 11
3 + 12
12 + 3
10 + 5
5 + 10
Can't roll the red ones AND the black ones above each red..... the dice are marked differently......
first answerer missed 11 - 4 so correct answer is 7 out of 36 or 7/36
