Let
f(x) = 9x + 16 if x < 2,
f(x) = 8x - 40 if x >= 2.
If f(x) = -2, find the sum of all possible values of x.
+179 First, we start by assuming that x < 2.
Thus, it must satisfy the equation f(x) = 9x+16 = -2.
9x+16= -2.
9x = -18
x= -2.
Because this is < 2, we know that x = -2 is a solution.
Now for the second case, namely, x ≥ 2.
8x-40 = -2
8x= 38
x= 4.75
Because 4.75 ≥ 2, this solution is also valid.
From the above method, we can decide that the sum of the possible values of x are -2 + 4.75, or 2.75
+179 First, we start by assuming that x < 2.
Thus, it must satisfy the equation f(x) = 9x+16 = -2.
9x+16= -2.
9x = -18
x= -2.
Because this is < 2, we know that x = -2 is a solution.
Now for the second case, namely, x ≥ 2.
8x-40 = -2
8x= 38
x= 4.75
Because 4.75 ≥ 2, this solution is also valid.
From the above method, we can decide that the sum of the possible values of x are -2 + 4.75, or 2.75
