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# Help function

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Let

f(x) = 9x + 16 if x < 2,

f(x) = 8x - 40 if x >= 2.

If f(x) = -2, find the sum of all possible values of x.

Jun 18, 2021

#1
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First, we start by assuming that x < 2.

Thus, it must satisfy the equation f(x) = 9x+16 = -2.

9x+16= -2.

9x = -18

x= -2.

Because this is < 2, we know that x = -2 is a solution.

Now for the second case, namely, x ≥ 2.

8x-40 = -2

8x= 38

x= 4.75

Because 4.75 ≥ 2, this solution is also valid.

From the above method, we can decide that the sum of the possible values of x are -2 + 4.75, or 2.75

Jun 18, 2021

#1
+2

First, we start by assuming that x < 2.

Thus, it must satisfy the equation f(x) = 9x+16 = -2.

9x+16= -2.

9x = -18

x= -2.

Because this is < 2, we know that x = -2 is a solution.

Now for the second case, namely, x ≥ 2.

8x-40 = -2

8x= 38

x= 4.75

Because 4.75 ≥ 2, this solution is also valid.

From the above method, we can decide that the sum of the possible values of x are -2 + 4.75, or 2.75

EnchantedLava68 Jun 18, 2021