In triangle ABC, point X is on side BC such that AX=13,BX=10,CX=10, and the circumcircles of triangles ABX and ACX have the same radius. Find the area of triangle ABC.

I think that the answer is 130. I drew a diagram and place A, B, and C on random corners. BC has X, so I place X in the middle of BC. AX is 13, which is the height, and BC is 20, because 10 + 10 is 20, so 20 is the width. 20 * 13 / 2 is 10 * 13, or 130.