In rectangle ABCD, shown here, CE is perpendicular to BD. If BC = 3 and DC = 3, what is CE?

Guest Jul 11, 2021

#1**+3 **

Answer: \(1.5\sqrt2\)

Solution:

If BC and DC are equal to each other (they are both three), then ABCD must be a square. BD would just be a diagonal of said square, splitting it in half. CE at that ponit is obviously just 1/2 of BD, and BD is \(3\sqrt2\) (\(\sqrt(3\cdot3+3\cdot3)\), as according to the Pythagorean theorem). Multiplying those two together gives an answer of \(1.5\sqrt2\).

WhyamIdoingthis Jul 11, 2021