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In triangle ABC, CA = 4sqrt2, CB = 4sqrt3, and angle A = 45 degrees. What is B in degrees?

 Jun 22, 2022
 #1
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angle B = 120 degrees.

 Jun 22, 2022
 #2
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sin A  / CB  =   sin B / AC

 

sin (45)  / (4sqrt 3)  =  sin B  / (4 sqrt2)

 

(1/sqrt 2)  / sqrt 3  =  sin B / (sqrt 2)

 

1 /sqrt (3)  = sin B

 

arcsin (1/sqrt 3)  = B  ≈  35.26°

 

 

cool cool cool

 Jun 22, 2022

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