In triangle ABC, CA = 4sqrt2, CB = 4sqrt3, and angle A = 45 degrees. What is B in degrees?
angle B = 120 degrees.
sin A / CB = sin B / AC
sin (45) / (4sqrt 3) = sin B / (4 sqrt2)
(1/sqrt 2) / sqrt 3 = sin B / (sqrt 2)
1 /sqrt (3) = sin B
arcsin (1/sqrt 3) = B ≈ 35.26°
