1) Let ABCDE be a regular pentagon. Prove that AC bisects angle BCE and AD bisects angle BDE.
2) In quadrilateral BCDE, CBD = 31 degrees, CED = 47 degrees, BCE = 85 degrees. Find angle BDE.
+526 It would be easier for us if you'd enclose a diagram with question especially geometry. Anyway,
2) ∠BDE + ∠CBD + ∠CED + ∠BCE = 360
∠BDE + 31 + 47 + 85 = 360
∠BDE = 360 - 163 = 197°
