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There are two different isosceles triangles whose side lengths are integers and whose areas are 120(sorry).One of these two triangles,  has two sides with length 17 and one with length 30. Determine the perimeter of the second triangle.

 

 Mar 1, 2019
edited by Guest  Mar 1, 2019
 #1
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Whose areas are what?

 Mar 1, 2019
 #2
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We have that

 

120 = (1/2) b*h

 

240 = b * h

 

b = 240/h

 

If h = 15, then b = 16   and (1/2)b  = (1/2)(16) = 8

 

So....we have a right triangle   with legs of 8 and 15

So....the side of this triangle = 17

 

So....the perimeter of this triangle is   17, 17, 16 =   50

 

 

cool cool cool

 Mar 1, 2019

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