#1**+3 **

since in $\triangle ABC$, $\overset{-}{AB}=\overset{-}{AC}$, it means that it is an isosceles triangle, which also means that both angles at the bottom are going to be the same

so we know that $\angle ABC=\angle ACB=50^\circ$

by adding the two you get $50^\circ+50^\circ=100^\circ$

a triangle's interior angle are equal to $180^\circ$

knowing that $ \angle ABC+\angle ACB+ \angle BAC=180^\circ $, by plugging in what we have we get $ 100^\circ+\angle BAC=180^\circ $

$ \angle BAC=180^\circ-100^\circ $

$ \boxed{ \angle BAC=80^\circ } $

UsernameTooShort Jun 25, 2021

#1**+3 **

Best Answer

since in $\triangle ABC$, $\overset{-}{AB}=\overset{-}{AC}$, it means that it is an isosceles triangle, which also means that both angles at the bottom are going to be the same

so we know that $\angle ABC=\angle ACB=50^\circ$

by adding the two you get $50^\circ+50^\circ=100^\circ$

a triangle's interior angle are equal to $180^\circ$

knowing that $ \angle ABC+\angle ACB+ \angle BAC=180^\circ $, by plugging in what we have we get $ 100^\circ+\angle BAC=180^\circ $

$ \angle BAC=180^\circ-100^\circ $

$ \boxed{ \angle BAC=80^\circ } $

UsernameTooShort Jun 25, 2021