I am really stuck on this
In how many ways can three pairs of siblings from different families be seated in two rows of three chairs, if siblings may sit next to each other in the same row, but no child may sit directly in front of their sibling?
+184 Disregarding the fact that no child can sit directly in front of their sibling, there are 6! = 6x5x4x3x2x1 ways, which is 720 ways in total. Then count how many ways siblings can sit in front of each other. Each person can sit in 3 spots with a sibling in front of them. The rest should be easy. You'll need to check because I might be wrong haha.
