#1**+5 **

We can use the distance formula process here....I think this might be confusing to you because there are no "numbers" involved!!! Right???

I like to do it this way.........

Subtract the "x" coordinates in any order....so (4a - 3a) = a

Now, subtract the y coordinates in any order......so (√3)a - 0 = (√3)a

Now......square both things......this gives......a^{2} and [(√3)a]^{2} = a^{2} and 3a^{2}

Now, add them together = 4a^{2} ......Now....take the square root of this = 2a

And there you go!!!

CPhill Jul 10, 2014

#2**0 **

Geometry is so weird... lol thank you so very much :) I think I am getting the concept :D

Rose98 Jul 10, 2014