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In triangle \(ABC\), the angles \(\angle A\)\(\angle B\)\(\angle C\) form an arithmetic sequence, I think in that order. If \(\angle A = 27^\circ\), then what is \(\angle C\), in degrees?

 

~PikachuLovesKetchup

 

P.S. I'm in 5th grade (don't judge!)

 Feb 10, 2022
edited by Guest  Feb 10, 2022
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If Angle A is 27 degrees, and A, B, and C form an arithmatic sequence in that order, then we can say that:

 

A + (A + d) + (A + 2d) = 180, where d is the common difference.

= 27 + (27 + d) + (27 + 2d) = 180

 

You can then solve for d, and thus solve for C.

 

Hope this helped! Let me know if I did anything wrong! If you don't understand my method then you can reply and I will do my best to explain more thoroughly!

 Feb 10, 2022
 #2
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It sure helped! I hadn't thought of the equation. Thanks InhumanCalculator!

 

~ PikachuLovesKetchup

 Feb 10, 2022

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