In triangle \(ABC\), the angles \(\angle A\), \(\angle B\), \(\angle C\) form an arithmetic sequence, I think in that order. If \(\angle A = 27^\circ\), then what is \(\angle C\), in degrees?
P.S. I'm in 5th grade (don't judge!)
If Angle A is 27 degrees, and A, B, and C form an arithmatic sequence in that order, then we can say that:
A + (A + d) + (A + 2d) = 180, where d is the common difference.
= 27 + (27 + d) + (27 + 2d) = 180
You can then solve for d, and thus solve for C.
Hope this helped! Let me know if I did anything wrong! If you don't understand my method then you can reply and I will do my best to explain more thoroughly!