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# Help.. I'm stuck and need help fast.

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Find the ordered triple$$(p, q, r)$$  that satisfies the following system:

\begin{align*} p-2q&=0\\ q-2r&=0\\ p+r&=5. \end{align*}

Aug 16, 2022

#1
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From the first equation and second equations, we have $$p = 2q$$ and $$q = 2r$$, meaning $$p = 2 \times 2r = 4r$$

Substituting this into the third equation gives us $$r = 1$$. Plugging this value into the second equation gives us $$q - 2 = 0$$, meaning $$q = 2$$

Finally, substituting $$q = 2$$ into the first equation $$p - 4 = 0$$, meaning $$p = 4$$

So, the solution is $$\color{brown}\boxed{(4,2,1)}$$

Aug 16, 2022
#2
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Thank you so much BuilderBoy!

Guest Aug 16, 2022