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Find the ordered triple\((p, q, r)\)  that satisfies the following system:

\(\begin{align*} p-2q&=0\\ q-2r&=0\\ p+r&=5. \end{align*}\)

 Aug 16, 2022
 #1
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From the first equation and second equations, we have \(p = 2q\) and \(q = 2r\), meaning \(p = 2 \times 2r = 4r\)

 

Substituting this into the third equation gives us \(r = 1\). Plugging this value into the second equation gives us \(q - 2 = 0\), meaning \(q = 2\)

 

Finally, substituting \(q = 2\) into the first equation \(p - 4 = 0 \), meaning \(p = 4\)

 

So, the solution is \(\color{brown}\boxed{(4,2,1)}\)

 Aug 16, 2022
 #2
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Thank you so much BuilderBoy!laugh

Guest Aug 16, 2022

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